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Question

Solid angle made by plane surfaces $\Omega=2 	imes 2 \pi(1-\cos 	heta)$

$\Rightarrow \Omega=4 \pi-4 \pi \cos 	heta$

So solid angle made by cu

Vedclass · Accepted Answer

$3$

Vedclass · Answer

Solid angle made by plane surfaces $\Omega=2 	imes 2 \pi(1-\cos 	heta)$

$\Rightarrow \Omega=4 \pi-4 \pi \cos 	heta$

So solid angle made by curved surface $=4 \pi-\Omega$

$=4 \pi-(4 \pi-4 \pi \cos 	heta)=4 \pi \cos 	heta$

$\phi_{30^{\circ}}=\phi=\frac{4 \pi \cos 30^{\circ}}{4 \pi} \frac{ Q }{\epsilon_0}=\cos 30^{\circ} \frac{ Q }{\epsilon_0}$

$\phi_{60}=\frac{4 \pi \cos 60^{\circ}}{4 \pi} \frac{ Q }{\epsilon_0}=\cos 60^{\circ} \frac{ Q }{\epsilon_0}$

$\frac{\phi_{30}}{\phi_{60}}=\frac{\cos 30^{\circ}}{\cos 60^{\circ}}=\sqrt{3}$

$\frac{\phi}{\phi_{60}}=\sqrt{3}$

$\phi_{60}=\frac{\phi}{\sqrt{3}} \Rightarrow n =3$

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