A charge $q$ is located at the centre of a cube. The electric flux through any face is
A charge $q$ is located at the centre of a cube. The electric flux through any face is
- [AIPMT 2003]
- A
$\frac{{4\pi q}}{{6(4\pi {\varepsilon _0})}}$
- B
$\frac{{\pi q}}{{6(4\pi {\varepsilon _0})}}$
- C
$\frac{q}{{6(4\pi {\varepsilon _0})}}$
- D
$\frac{{2\pi q}}{{6(4\pi {\varepsilon _0})}}$
Similar Questions
In finding the electric field using Gauss Law the formula $|\overrightarrow{\mathrm{E}}|=\frac{q_{\mathrm{enc}}}{\varepsilon_{0}|\mathrm{A}|}$ is applicable. In the formula $\varepsilon_{0}$ is permittivity of free space, $A$ is the area of Gaussian surface and $q_{enc}$ is charge enclosed by the Gaussian surface. The equation can be used in which of the following situation?
In finding the electric field using Gauss Law the formula $|\overrightarrow{\mathrm{E}}|=\frac{q_{\mathrm{enc}}}{\varepsilon_{0}|\mathrm{A}|}$ is applicable. In the formula $\varepsilon_{0}$ is permittivity of free space, $A$ is the area of Gaussian surface and $q_{enc}$ is charge enclosed by the Gaussian surface. The equation can be used in which of the following situation?
- [JEE MAIN 2020]
Give characteristics of electric field lines.
Give characteristics of electric field lines.
Gauss's law can help in easy calculation of electric field due to
Gauss's law can help in easy calculation of electric field due to
A charge $Q$ is situated at the comer of a cube, the electric flux passed through all the six faces of the cube is
A charge $Q$ is situated at the comer of a cube, the electric flux passed through all the six faces of the cube is
- [AIPMT 2000]
The electric field components in Figure are $E_{x}=\alpha x^{1 / 2}, E_{y}=E_{z}=0,$ in which $\alpha=800 \;N / C\, m ^{1 / 2} .$ Calculate
$(a)$ the flux through the cube, and
$(b)$ the charge within the cube. Assume that $a=0.1 \;m$
The electric field components in Figure are $E_{x}=\alpha x^{1 / 2}, E_{y}=E_{z}=0,$ in which $\alpha=800 \;N / C\, m ^{1 / 2} .$ Calculate
$(a)$ the flux through the cube, and
$(b)$ the charge within the cube. Assume that $a=0.1 \;m$