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1. Electric Charges and Fields
medium
A charge of $4\,\mu C$ is to be divided into two. The distance between the two divided charges is constant. The magnitude of the divided charges so that the force between them is maximum, will be.
A
$1\; \mu C$ and $3\; \mu C$
B
$2\; \mu C$ and $2\; \mu C$
C
$0$ and $4\; \mu C$
D
$1.5\; \mu C$ and $2.5\; \mu C$
(JEE MAIN-2022)
Solution
$F =\frac{ Kq (4- q )}{ d ^{2}}$
$\frac{ dF }{ dq }=\frac{ K }{ d ^{2}}[4-2 q ]=0$
$q =2$
Standard 12
Physics
