1. Electric Charges and Fields
easy

A charged particle $q$ is placed at the centre $O$ of cube of length $L$ $(A\,B\,C\,D\,E\,F\,G\,H)$. Another same charge $q$ is placed at a distance $L$ from $O$.Then the electric flux through $BGFC$ is

A

$q/4\pi {\varepsilon_{0}}L$

B

zero

C

$q/2\pi {\varepsilon_{0}}L$

D

$q/3\pi {\varepsilon_{0}}L$

(AIIMS-2013) (AIEEE-2002)

Solution

The flux for both the charges exactly cancels the effect of each other.

Standard 12
Physics

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