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1. Electric Charges and Fields
easy
A charged particle $q$ is placed at the centre $O$ of cube of length $L$ $(A\,B\,C\,D\,E\,F\,G\,H)$. Another same charge $q$ is placed at a distance $L$ from $O$.Then the electric flux through $BGFC$ is

A
$q/4\pi {\varepsilon_{0}}L$
B
zero
C
$q/2\pi {\varepsilon_{0}}L$
D
$q/3\pi {\varepsilon_{0}}L$
(AIIMS-2013) (AIEEE-2002)
Solution
The flux for both the charges exactly cancels the effect of each other.
Standard 12
Physics
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