Gujarati
4.Moving Charges and Magnetism
medium

A charged particle is moving in a uniform magnetic field in a circular path. Radius of circular path is $R$. When energy of particle is doubled, then new radius will be

A

$R\sqrt 2 $

B

$R\sqrt 3 $

C

$2\, R$

D

$3\, R$

Solution

(a) $r = \frac{{\sqrt {2mK} }}{{qB}} \Rightarrow r \propto \sqrt K $ $ \Rightarrow \frac{R}{{{R_2}}} = \sqrt {\frac{K}{{2K}}} \Rightarrow {R_2} = R\sqrt 2 $

Standard 12
Physics

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