A charged particle moves through a magnetic field perpendicular to its direction. Then
both momentum and kinetic energy of the particle are not constant
both momentum and kinetic energy of the particle are constant
kinetic energy changes but the momentum is constant
the momentum changes but the kinetic energy is constant
Two protons move parallel to each other, keeping distance $r$ between them, both moving with same velocity $\vec V\,$. Then the ratio of the electric and magnetic force of interaction between them is
A proton and an $\alpha$ -particle, having kinetic energies $K _{ p }$ and $K _{\alpha},$ respectively, enter into $a$ magnetic field at right angles.
The ratio of the radii of trajectory of proton to that of $\alpha$ -particle is $2: 1 .$ The ratio of $K _{ p }: K _{\alpha}$ is :
A magnetic field
A deutron of kinetic energy $50\, keV$ is describing a circular orbit of radius $0.5$ $metre$ in a plane perpendicular to magnetic field $\overrightarrow B $. The kinetic energy of the proton that describes a circular orbit of radius $0.5$ $metre$ in the same plane with the same $\overrightarrow B $ is........$keV$
The region between $y = 0$ and $y = d$ contains a magnetic field $\vec B = B\hat z$ A particle of mass $m$ and charge $q$ enters the region with a velocity $\vec v = v\hat i$. If $d = \frac{{mv}}{{2qB}}$ , the acceleration of the charged particle at the point of its emergence at the other side is