A charged particle of mass m and charge q travels on a circular path of radius r that is perpendicul

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4.Moving Charges and Magnetism

easy

A charged particle of mass $m$ and charge $q$ travels on a circular path of radius $r$ that is perpendicular to a magnetic field $B$. The time taken by the particle to complete one revolution is

A

$\frac{{2\pi qB}}{m}$

B

$\frac{{2\pi \,m}}{{q\,B}}$

C

$\frac{{2\pi \,m\,q}}{B}$

D

$\frac{{2\pi \,{q^2}B}}{m}$

(AIEEE-2005)

Solution

(b) Equating magnetic force to centripetal force,

$\frac{m v^{2}}{r}=q v B \sin 90^{\circ}$

Time to complete one revolution,

$T=\frac{2 \pi r}{v}=\frac{2 \pi m}{q B}$

Standard 12

Physics

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