A coin is tossed $4$ times. The probability that at least one head turns up is
A coin is tossed $4$ times. The probability that at least one head turns up is
- A
$\frac{1}{{16}}$
- B
$\frac{2}{{16}}$
- C
$\frac{{14}}{{16}}$
- D
$\frac{{15}}{{16}}$
Similar Questions
A die has two faces each with number $^{\prime}1^{\prime}$ , three faces each with number $^{\prime}2^{\prime}$ and one face with number $^{\prime}3^{\prime}$. If die is rolled once, determine $P(1$ or $3)$
A die has two faces each with number $^{\prime}1^{\prime}$ , three faces each with number $^{\prime}2^{\prime}$ and one face with number $^{\prime}3^{\prime}$. If die is rolled once, determine $P(1$ or $3)$
In order to get at least once a head with probability $ \ge 0.9,$ the number of times a coin needs to be tossed is
In order to get at least once a head with probability $ \ge 0.9,$ the number of times a coin needs to be tossed is
If $A$ is a sure event, then the value of $P (A$ not ) is
If $A$ is a sure event, then the value of $P (A$ not ) is
The probability of a sure event is
The probability of a sure event is
For three non impossible events $A$, $B$ and $C$ $P\left( {A \cap B \cap C} \right) = 0,P\left( {A \cup B \cup C} \right) = \frac{3}{4},$ $P\left( {A \cap B} \right) = \frac{1}{3}$ and $P\left( C \right) = \frac{1}{6}$.
The probability, exactly one of $A$ or $B$ occurs but $C$ doesn't occur is
For three non impossible events $A$, $B$ and $C$ $P\left( {A \cap B \cap C} \right) = 0,P\left( {A \cup B \cup C} \right) = \frac{3}{4},$ $P\left( {A \cap B} \right) = \frac{1}{3}$ and $P\left( C \right) = \frac{1}{6}$.
The probability, exactly one of $A$ or $B$ occurs but $C$ doesn't occur is