If $P(A) = 0.65,\,\,P(B) = 0.15,$ then $P(\bar A) + P(\bar B) = $
$1.5$
$1.2$
$0.8$
None of these
(b) $P(\bar A) + P(\bar B) = 0.35 + 0.85 = 1.2$.
One card is drawn from each of two ordinary packs of $52$ cards. The probability that at least one of them is an ace of heart, is
Two dice are thrown. The events $A, B$ and $C$ are as follows:
$A:$ getting an even number on the first die.
$B:$ getting an odd number on the first die.
$C:$ getting the sum of the numbers on the dice $\leq 5$
Describe the events $A$ but not $C$
Two dice are thrown together. The probability that sum of the two numbers will be a multiple of $4$ is
Let $A$ be a set of all $4 -$digit natural numbers whose exactly one digit is $7 .$ Then the probability that a randomly chosen element of $A$ leaves remainder $2$ when divided by $5$ is ….. .
An integer is chosen at random and squared. The probability that the last digit of the square is $1$ or $5$ is
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