Gujarati
1. Electric Charges and Fields
medium

A conducting sphere of radius $R$, and carrying a charge $q$ is joined to a conducting sphere of radius $2R$, and carrying a charge $-2q$. The charge flowing between them will be

A

$\frac{q}{3}$

B

$\frac{{2q}}{3}$

C

$q$

D

$\frac{{4q}}{3}$

Solution

(d) Initial charge on sphere of radius $R = q$
Charge on this sphere after joining $q' = \frac{{(q + ( – 2q) \times R}}{{R + 2R}}$ $ = \frac{{ – q \times R}}{{3R}} = – \frac{q}{3}$
Now charge flowing between them $ = q – \left( { – \frac{q}{3}} \right) = \frac{{4q}}{3}$

Standard 12
Physics

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