A total charge $Q$ is broken in two parts ${Q_1}$ and ${Q_2}$ and they are placed at a distance $R$ from each other. The maximum force of repulsion between them will occur, when
${Q_2} = \frac{Q}{R},\;{Q_1} = Q - \frac{Q}{R}$
${Q_2} = \frac{Q}{4},\;{Q_1} = Q - \frac{{2Q}}{3}$
${Q_2} = \frac{Q}{4},\;{Q_1} = \frac{{3Q}}{4}$
${Q_1} = \frac{Q}{2},\;{Q_2} = \frac{Q}{2}$
By using Coulomb’s law, define unit charge.
Three point charges of magnitude $5 \mu C , 0.16 \mu C$ and $0.3 \mu C$ are located at the vertices $A , B , C$ of a right angled triangle whose sides are $AB =3\,cm$, $BC =3 \sqrt{2}\,cm$ and $CA =3\,cm$ and point $A$ is the right angle corner. Charge at point $A$ experiences
$N$ of electrostatic force due to the other two charges.
Two small spheres each of mass $10 \,mg$ are suspended from a point by threads $0.5 \,m$ long. They are equally charged and repel each other to a distance of $0.20 \,m$. The charge on each of the sphere is $\frac{ a }{21} \times 10^{-8} \, C$. The value of $a$ will be ...... .
$\left[\right.$ Given $\left.g=10 \,ms ^{-2}\right]$
Three charges are placed as shown in figure. The magnitude of $q_1$ is $2.00\, \mu C$, but its sign and the value of the charge $q_2$ are not known. Charge $q_3$ is $+4.00\, \mu C$, and the net force on $q_3$ is entirely in the negative $x-$ direction. As per the condition given the sign of $q_1$ and $q_2$ will be
An isolated solid metallic sphere is given $ + Q$ charge. The charge will be distributed on the sphere