A conical pendulum of length 1,m makes an ang | vedclass

Name: PDF Generator App | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

$\begin{array}{l} Given,	heta  = {45^ \circ },r = 0.4m,g = 10m/{s^2}\ T\,\sin \,	heta  = \frac{{m{v^2}}}{r}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,

Vedclass · Accepted Answer

$2$

Vedclass · Answer

$\begin{array}{l} Given,	heta  = {45^ \circ },r = 0.4m,g = 10m/{s^2}\ T\,\sin \,	heta  = \frac{{m{v^2}}}{r}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,...\left( i ight)\ T\,\cos \,	heta  = mg\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,....\left( {ii} ight)\ From\,equation\,\left( i ight) and \left( {ii} ight)\ We\,have,\,	an 	heta  = \frac{{{v^2}}}{{rg}}\ {V^2} = rg\,\,\,\,\,\,\,\,\,\,\,\,	heta  = {45^ \circ }\ Hence,\,speed\,of\,the\,pendulum\,in\,its\,circular\ path,\ V = \sqrt {rg}  = \sqrt {0.4 	imes 10}  = 2m/s \end{array}$

Similar Questions

A stone of mass $0.3\,kg$ attached to a $1.5\,m$ long string is whirled around in a horizontal circle at a speed of $6\,m s ^{-1}$. The tension in the string is $............\,N$

If speed of a particle moving in a circle of radius $2\,m$ is given as $v = 2t + 2$, then its centripetal acceleration after $1\, s$ will be ......... $m/s^2$

The angular speed of earth around its own axis is ......... $rad / s$

If a particle is moving on a circular path with constant speed, then the angle between the direction of acceleration and its position vector w.r.t. centre of circle will be ............

The average acceleration vector for a particle having a uniform circular motion is