4-1.Newton's Laws of Motion
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$3.0\, kg$ संहति के किसी पिण्ड पर आरोपित कोई बल $25\, s$ में उसकी चाल को $2.0\, m s ^{-1}$ से $3.5\, m s ^{-1}$ कर देता है। पिण्ड की गति की दिशा अपरिवर्तित रहती है। बल का परिमाण व दिशा क्या है ?

Option A
Option B
Option C
Option D

Solution

$0.18 \,N ;$ in the direction of motion of the body

Mass of the body, $m=3 \,kg$

Initial speed of the body, $u=2\, m / s$

Final speed of the body, $v=3.5 \,m / s$

Time, $t=25 \,s$

Using the first equation of motion, the acceleration ( $a$ ) produced in the body can

be calculated as: $v=u+a t$

$\therefore a=\frac{v-u}{t}$

$=\frac{3.5-2}{25}=\frac{1.5}{25}=0.06\, m / s ^{2}$

As per Newton's second law of motion, force is given as:

$F=m a$

$=3 \times 0.06=0.18\, N$

since the application of force does not change the direction of the body, the net force acting on the body is in the direction of its motion.

Standard 11
Physics

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