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4-1.Newton's Laws of Motion
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A cricketer catches a ball of mass $150\; gm$ in $0.1$ second moving with speed $20\, m/s$. Then he experiences force of ..... $N$
A$0.3$
B$30 $
C$300$
D$3000$
Solution
(b)Force exerted by the ball on hands of the player
$ = \frac{{mdv}}{{dt}} = \frac{{0.15 \times 20}}{{0.1}} = 30\;N$
$ = \frac{{mdv}}{{dt}} = \frac{{0.15 \times 20}}{{0.1}} = 30\;N$
Standard 11
Physics
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