A cricketer scored some runs in his continuous 9 innings. He scored 100 runs in his 10^{th} innings

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4.Average

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A cricketer scored some runs in his continuous $9$ innings. He scored $100$ runs in his $10^{th}$ innings and this increased his average by $8$ runs. What was the average of his runs at the end of $10^{th}$ innings?

A

$20$

B

$24$

C

$28$

D

$32$

Solution

Let average of $9$ innings $=x,$ Total run $=9 x$ According to the question

$\frac{9 x+100}{10}=x+8 \quad 9 x+100=10 x+80 \Rightarrow x=20$

Average after $10$ innings $=20+8=28$

Standard 13

Quantitative Aptitude

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