If y = {1 over {a - z}}, then {{dz} over {dy}} =

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If $y = {1 \over {a - z}},$then ${{dz} \over {dy}} = $

A${(z - a)^2}$

B$ - {(z - a)^2}$

C${(z + a)^2}$

D$ - {(z + a)^2}$

Solution

(a) Here $V = \frac{4}{3}\pi {r^3}$==> $\frac{{dz}}{{dy}} = \frac{1}{{{y^2}}} = {(a – z)^2}$

Standard 11

Physics

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