A cup of coffee cools from $90^{\circ} \mathrm{C}$ to $80^{\circ} \mathrm{C}$ in $\mathrm{t}$ minutes, when the room temperature is $20^{\circ} \mathrm{C}$. The time taken by a similar cup of coffee to cool from $80^{\circ} \mathrm{C}$ to $60^{\circ} \mathrm{C}$ at a room temperature same at $20^{\circ} \mathrm{C}$ is :
A cup of coffee cools from $90^{\circ} \mathrm{C}$ to $80^{\circ} \mathrm{C}$ in $\mathrm{t}$ minutes, when the room temperature is $20^{\circ} \mathrm{C}$. The time taken by a similar cup of coffee to cool from $80^{\circ} \mathrm{C}$ to $60^{\circ} \mathrm{C}$ at a room temperature same at $20^{\circ} \mathrm{C}$ is :
- [NEET 2021]
- A
$\frac{13}{10} \mathrm{t}$
- B
$\frac{13}{5} \mathrm{t}$
- C
$\frac{10}{13} \mathrm{t}$
- D
$\frac{5}{13} \mathrm{t}$
Similar Questions
Ice is used in a cooler in order to cool its contents. Which of the following will speed up the cooling process?
Ice is used in a cooler in order to cool its contents. Which of the following will speed up the cooling process?
- [KVPY 2014]
If a piece of metal is heated to temperature $\theta$ and then allowed to cool in a room which is at temperature $\theta_0$, the graph between the temperature $T$ of the metal and time t will be closest to
If a piece of metal is heated to temperature $\theta$ and then allowed to cool in a room which is at temperature $\theta_0$, the graph between the temperature $T$ of the metal and time t will be closest to
- [JEE MAIN 2013]
A body cools from $60\,^oC$ to $50\,^oC$ in $10\,minutes$ . If the room temperature is $25\,^oC$ and assuming Newton's law of cooling to hold good, the temperature of the body at the end of the next $10\,minutes$ will be ......... $^oC$
A body cools from $60\,^oC$ to $50\,^oC$ in $10\,minutes$ . If the room temperature is $25\,^oC$ and assuming Newton's law of cooling to hold good, the temperature of the body at the end of the next $10\,minutes$ will be ......... $^oC$
A cane is taken out from a refrigerator at $0°C$ . The atmospheric temperature is $25°C$ . If $t_1$ is the time taken to heat from $0°C$ to $5°C$ and $t_2$ is the time taken from $10°C$ to $15°C$, then
A cane is taken out from a refrigerator at $0°C$ . The atmospheric temperature is $25°C$ . If $t_1$ is the time taken to heat from $0°C$ to $5°C$ and $t_2$ is the time taken from $10°C$ to $15°C$, then
A body takes $10$ minutes to cool down from $62^o C$ to $50^o C$. If the temperature of surrounding is $26^o C$ then in the next $10$ minutes temperature of the body will be ......... $^oC$
A body takes $10$ minutes to cool down from $62^o C$ to $50^o C$. If the temperature of surrounding is $26^o C$ then in the next $10$ minutes temperature of the body will be ......... $^oC$