11.Thermodynamics
hard

A diatomic gas, having $C_{p}=\frac{7}{2} R$ and $C _{ v }=\frac{5}{2} R ,$ is heated at constant pressure. The ratio $dU : dQ : dW :$

A

$5: 7: 3$

B

$5: 7: 2$

C

$3: 7: 2$

D

$3: 5: 2$

(JEE MAIN-2021)

Solution

$d U = n C _{ v } dT$

$dQ = nC _{ p } dT$

$dW = PdV = nRdT$ (isobaric process)

$d U : dQ : dW : C _{ v }: C _{ p }: R$

$=\frac{5 R }{2}: \frac{7 R }{2} \cdot R =5: 7: 2$

Standard 11
Physics

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