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11.Thermodynamics
easy
In the cyclic process shown in the figure, the work done by the gas in one cycle is

A
$28\,{P_1}{V_1}$
B
$14\,{P_1}{V_1}$
C
$18\,{P_1}{V_1}$
D
$9\,{P_1}{V_1}$
Solution
(d) Work done = Area under curve $ = \frac{{6{P_1} \times 3{V_1}}}{2}= 9 P_1V_1$
Standard 11
Physics