11.Thermodynamics
easy

In the cyclic process shown in the figure, the work done by the gas in one cycle is

A

$28\,{P_1}{V_1}$

B

$14\,{P_1}{V_1}$

C

$18\,{P_1}{V_1}$

D

$9\,{P_1}{V_1}$

Solution

(d) Work done = Area under curve $ = \frac{{6{P_1} \times 3{V_1}}}{2}= 9 P_1V_1$

Standard 11
Physics

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