A die has two faces each with number $^{\prime}1^{\prime}$ , three faces each with number $^{\prime}2^{\prime}$ and one face with number $^{\prime}3^{\prime}$. If die is rolled once, determine $P(1$ or $3)$

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Total number of faces $=6$

$P(1$ or $3)=P(\text { not } 2)=1-P(2)=1-\frac{1}{2}=\frac{1}{2}$

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