A die has two faces each with number ^{prime}1^{prime} , three faces each with number ^{prime}2^{pri

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14.Probability

easy

A die has two faces each with number $^{\prime}1^{\prime}$ , three faces each with number $^{\prime}2^{\prime}$ and one face with number $^{\prime}3^{\prime}$. If die is rolled once, determine $P(1$ or $3)$

A

$\frac{1}{2}$

B

$\frac{1}{2}$

C

$\frac{1}{2}$

D

$\frac{1}{2}$

Solution

Total number of faces $=6$

$P(1$ or $3)=P(\text { not } 2)=1-P(2)=1-\frac{1}{2}=\frac{1}{2}$

Standard 11

Mathematics

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