14.Probability
easy

एक पासा फेंका जाता है। निम्नलिखित घटनाओं की प्रायिकता ज्ञात कीजिए

एक अभाज्य संख्या प्रकट होना

A

$\frac{1}{2}$

B

$\frac{1}{2}$

C

$\frac{1}{2}$

D

$\frac{1}{2}$

Solution

The sample space of the given experiment is given by

$S=\{1,2,3,4,5,6\}$

Let $A $ be the event of the occurrence of a prime number.

Accordingly, $A=\{2,3,5\}$

$\therefore P(A)=\frac{\text { Number of outcomes favourable to } A }{\text { Total number of possible outcomes }}=\frac{n(A)}{n(S)}=\frac{3}{6}=\frac{1}{2}$

Standard 11
Mathematics

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