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14.Probability
easy
एक पासा फेंका जाता है। निम्नलिखित घटनाओं की प्रायिकता ज्ञात कीजिए
एक अभाज्य संख्या प्रकट होना
A
$\frac{1}{2}$
B
$\frac{1}{2}$
C
$\frac{1}{2}$
D
$\frac{1}{2}$
Solution
The sample space of the given experiment is given by
$S=\{1,2,3,4,5,6\}$
Let $A $ be the event of the occurrence of a prime number.
Accordingly, $A=\{2,3,5\}$
$\therefore P(A)=\frac{\text { Number of outcomes favourable to } A }{\text { Total number of possible outcomes }}=\frac{n(A)}{n(S)}=\frac{3}{6}=\frac{1}{2}$
Standard 11
Mathematics