A die is thrown, find the probability of following events:A prime number will appear,
A die is thrown, find the probability of following events:A prime number will appear,
The sample space of the given experiment is given by
$S=\{1,2,3,4,5,6\}$
Let $A $ be the event of the occurrence of a prime number.
Accordingly, $A=\{2,3,5\}$
$\therefore P(A)=\frac{\text { Number of outcomes favourable to } A }{\text { Total number of possible outcomes }}=\frac{n(A)}{n(S)}=\frac{3}{6}=\frac{1}{2}$
Similar Questions
Describe the sample space for the indicated experiment : A die is thrown two times.
Describe the sample space for the indicated experiment : A die is thrown two times.
The chance of getting a doublet with $2$ dice is
The chance of getting a doublet with $2$ dice is
Two persons each make a single throw with a die. The probability they get equal value is ${p_1}$. Four persons each make a single throw and probability of three being equal is ${p_2}$, then
Two persons each make a single throw with a die. The probability they get equal value is ${p_1}$. Four persons each make a single throw and probability of three being equal is ${p_2}$, then
If $A$ is a sure event, then the value of $P (A$ not ) is
If $A$ is a sure event, then the value of $P (A$ not ) is
A die is thrown, find the probability of following events: A number greater than or equal to $3$ will appear.
A die is thrown, find the probability of following events: A number greater than or equal to $3$ will appear.