A dielectric slab of dielectric constant $K$ is placed between the plates of a parallel plate capacitor carrying charge $q$. The induced charge $q^{\prime}$ on the surface of slab is given by
A dielectric slab of dielectric constant $K$ is placed between the plates of a parallel plate capacitor carrying charge $q$. The induced charge $q^{\prime}$ on the surface of slab is given by
- A
$q^{\prime}=q-\frac{q}{K}$
- B
$q^{\prime}=-q+\frac{q}{K}$
- C
$q^{\prime}=q\left[\frac{1}{K}+1\right]$
- D
$q^{\prime}=-q\left(1+\frac{1}{K}\right)$
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