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2. Electric Potential and Capacitance
easy
A parallel plate capacitor is connected to a battery and a dielectric slab is inserted between the plates, then which quantity increase
A
potential difference
B
electric field
C
stored energy
D
$emf$ of battery
Solution
$U = \frac{1}{2}\,C{V^2}$
$C$ increase $\Rightarrow U$ increase
Standard 12
Physics
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