Gujarati
Hindi
1. Electric Charges and Fields
normal

A dipole having dipole moment $p$ is placed in front of a solid uncharged conducting  sphere are shown in the diagram. The net potential at point $A$ lying on the surface of the sphere is :-

A

$\frac{kp \cos \phi}{r^2  }$

B

$\frac{kp \cos^2 \phi}{r^2  }$

C

zero

D

$\frac{2kp \cos^2 \phi}{r^2  }$

Solution

$:$ If we want to find potential at $A$

$V_{A}=\frac{K_{p} \cos \phi}{r^{2}}$

$V_{A}=V_{0} \rightarrow$

$V_{0}=V_{\text {ind.}}+V_{\text {dipol.;}}$

$V_{i n d=0}$

$V_{0}=\frac{K_{p} \cos ^{2} \phi}{r^{2}}$

$V_{A}=V_{0}=\frac{K_{p} \cos ^{2} \phi}{r^{2}}$

Standard 12
Physics

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