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1. Electric Charges and Fields
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A dipole having dipole moment $p$ is placed in front of a solid uncharged conducting sphere are shown in the diagram. The net potential at point $A$ lying on the surface of the sphere is :-

A
$\frac{kp \cos \phi}{r^2 }$
B
$\frac{kp \cos^2 \phi}{r^2 }$
C
zero
D
$\frac{2kp \cos^2 \phi}{r^2 }$
Solution
$:$ If we want to find potential at $A$
$V_{A}=\frac{K_{p} \cos \phi}{r^{2}}$
$V_{A}=V_{0} \rightarrow$
$V_{0}=V_{\text {ind.}}+V_{\text {dipol.;}}$
$V_{i n d=0}$
$V_{0}=\frac{K_{p} \cos ^{2} \phi}{r^{2}}$
$V_{A}=V_{0}=\frac{K_{p} \cos ^{2} \phi}{r^{2}}$
Standard 12
Physics
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