3-1.Vectors
easy

A displacement vector of magnitude $4$ makes an angle $30^{\circ}$ with the $x$-axis. Its rectangular components in $x-y$ plane are .........

A

$2 \sqrt{3}, 2$

B

$4 \sqrt{3}, 4$

C

$\frac{2}{\sqrt{3}}, 2$

D

$\frac{4}{\sqrt{3}}, 4$

Solution

(a)

$|\vec{d}|=4 ~\\ x \text { component } =4 \cos 30^{\circ}$

$=4 \times \frac{\sqrt{3}}{2}$

$=2 \sqrt{3}$

$\text { y component } t =4 \times \sin 30^{\circ}$

$=4 \times 1 / 2$

$=2$

Standard 11
Physics

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