Two forces $P + Q$ and $P -Q$ make angle $2 \alpha$ with each other and their resultant make $\theta$ angle with bisector of angle between them. Then :
$P\, tan\, \theta = Q\, tan \, \alpha$
$P\, sin\, \theta = Q\, sin\, \alpha$
$P\, cos\, \alpha = Q\, sin\, \theta$
$P\, sin\, \alpha = Q\, sin\, \theta$
For the given vector $\vec A =3\hat i -4\hat j+10\hat k$ , the ratio of magnitude of its component on the $x-y$ plane and the component on $z-$ axis is
Two vectors $\overrightarrow a $ and $\overrightarrow b $ are at an angle of $60^o$ with each other. Their resultant makes an angle of $45^o$ with $\overrightarrow a $ . If $|\overrightarrow b | = 2\,units$ then $|\overrightarrow a |$ is:-
$Y $ component of velocity is $20$ and $X$ component of velocity is $10$. The direction of motion of the body with the horizontal at this instant is