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1. Electric Charges and Fields
easy
A drop of ${10^{ - 6}}\,kg$ water carries ${10^{ - 6}}\,C$ charge. What electric field should be applied to balance its weight (assume $g = 10\,m/{s^2}$)
A
$10\, V/m$ upward
B
$10\, V/m$ downward
C
$0.1\, V/m$ downward
D
$0.1\, V/m$ upward
Solution
(a) By using $QE = mg$
$==>$ $E = \frac{{mg}}{Q} = \frac{{{{10}^{ – 6}} \times 10}}{{{{10}^{ – 6}}}} = 10\,V/m;$ upward because charge is positive.
Standard 12
Physics