The insulation property of air breaks down at | vedclass

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Question

(b) $E = \frac{1}{{4\pi {\varepsilon _0}}} 	imes \frac{q}{{{r^2}}} = 9 	imes {10^9} 	imes \frac{q}{{{r^2}}}$
 $q = \frac{{E 	imes {r^2}}}{{9

Vedclass · Accepted Answer

$2 	imes {10^{ - 3}}$

Vedclass · Answer

(b) $E = \frac{1}{{4\pi {\varepsilon _0}}} 	imes \frac{q}{{{r^2}}} = 9 	imes {10^9} 	imes \frac{q}{{{r^2}}}$
 $q = \frac{{E 	imes {r^2}}}{{9 	imes {{10}^9}}} = \frac{{3 	imes {{10}^6} 	imes {{(2.5)}^2}}}{{9 	imes {{10}^9}}} = 2.0833 	imes {10^{ - 3}}$
q should be less than $2.0833 	imes {10^{ - 3}}$. In the given set of options $2 	imes {10^{ - 3}}$ is the maximum charge which is smaller than $2.0833 	imes {10^{ - 3}}$.

The insulation property of air breaks down at $E = 3 \times {10^6}$ $volt\,/\,metre$. The maximum charge that can be given to a sphere of diameter $5\,m$ is approximately (in coulombs)

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