Three charges are placed as shown in figure. magnitude of q₁ is 2.00, μ C , but its sign and valu

English

Gujarati

Hindi

1. Electric Charges and Fields

medium

Three charges are placed as shown in figure. The magnitude of $q_1$ is $2.00\, \mu C$, but its sign and the value of the charge $q_2$ are not known. Charge $q_3$ is $+4.00\, \mu C$, and the net force on $q_3$ is entirely in the negative $x-$ direction. The magnitude of $q_2$ is

$\frac{{27}}{{64}}\,\mu C$

$\frac{{27}}{{32}}\,\mu C$

$\frac{{13}}{{32}}\,\mu C$

$\frac{{13}}{{64}}\,\mu C$

Solution

The four possible force diagrams are shown in fig. Only the last picture can result in an electric field in the negative $\mathrm{x}$ – direction.

$\mathrm{q}_{1}=-2.00\, \mu \mathrm{C}, \mathrm{q}_{3}=+4.00 \,\mu \mathrm{C},$ and $\mathrm{q}_{2}>0$

as force on $\mathrm{q}_{3}$ is horizontal

so vertical component of $\mathrm{E}$ will be zero at $\mathrm{q}_{3}$ or $\quad \mathrm{E}_{y}=0$

${\therefore \mathrm{E}_{1} \sin \theta \quad \mathrm{E}_{2} \cos \theta} $

${\frac{\mathrm{k} \mathrm{q}_{1}}{\left(4 \times 10^{-2}\right)^{2}} \times \sin \theta=\frac{\mathrm{k} \mathrm{q}_{2}}{\left(3 \times 10^{-2}\right)} \cos \theta} $

${\mathrm{q}_{2}=\frac{9}{16} \times \tan \theta \times \mathrm{q}_{1}=\frac{9}{16} \times \frac{3}{4} \times 2\, \mu \mathrm{C}=\frac{27}{32}\, \mu \mathrm{C}}$

Standard 12

Physics

A total charge $q$ is divided as $q_1$ and $q_2$ which are kept at two of the vertices of an equilateral triangle of side a. The magnitude of the electric field $E$ at the third vertex of the triangle is to be depicted schematically as a function of $x=q_1 / q$. Choose the correct figure.

normal

(KVPY-2017)

Two equal negative charges $-\, q$ each are fixed at the points $(0, a)$ and $(0, -a)$ on the $Y$ -axis. A positive charge $Q$ is released from rest at the point $(2a, 0)$ on the $X$ -axis. The charge $Q$ will :-

medium

$(a)$ Consider an arbitrary electrostatic field configuration. A small test charge is placed at a null point (i.e., where $E =0$ ) of the configuration. Show that the equilibrium of the test charge is necessarily unstable.

$(b)$ Verify this result for the simple configuration of two charges of the same magnitude and sign placed a certain distance apart.

medium

The linear charge density on upper half of a segment of ring is $\lambda$ and at lower half, it is $-\lambda$. The direction of electrical field at centre $O$ of ring is :-

medium

Charges $Q _{1}$ and $Q _{2}$ arc at points $A$ and $B$ of a right angle triangle $OAB$ (see figure). The resultant electric field at point $O$ is perpendicular to the hypotenuse, then $Q _{1} / Q _{2}$ is proportional to

hard

(JEE MAIN-2020)

Three charges are placed as shown in figure. The magnitude of $q_1$ is $2.00\, \mu C$, but its sign and the value of the charge $q_2$ are not known. Charge $q_3$ is $+4.00\, \mu C$, and the net force on $q_3$ is entirely in the negative $x-$ direction. The magnitude of $q_2$ is

Solution

Similar Questions

A total charge $q$ is divided as $q_1$ and $q_2$ which are kept at two of the vertices of an equilateral triangle of side a. The magnitude of the electric field $E$ at the third vertex of the triangle is to be depicted schematically as a function of $x=q_1 / q$. Choose the correct figure.

Two equal negative charges $-\, q$ each are fixed at the points $(0, a)$ and $(0, -a)$ on the $Y$ -axis. A positive charge $Q$ is released from rest at the point $(2a, 0)$ on the $X$ -axis. The charge $Q$ will :-

The linear charge density on upper half of a segment of ring is $\lambda$ and at lower half, it is $-\lambda$. The direction of electrical field at centre $O$ of ring is :-

Charges $Q _{1}$ and $Q _{2}$ arc at points $A$ and $B$ of a right angle triangle $OAB$ (see figure). The resultant electric field at point $O$ is perpendicular to the hypotenuse, then $Q _{1} / Q _{2}$ is proportional to

Start a Free Trial Now