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3-2.Motion in Plane
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A fan is making $600$ revolutions per minute. If after some time it makes $1200 $ revolutions per minute, then increase in its angular velocity is
A$10\,\pi \,rad/\sec $
B$20\,\pi \,rad/\sec $
C$40\,\pi \,rad/\sec $
D$60\,\pi \,rad/\sec $
Solution
(b) Increment in angular velocity $\omega = 2\pi ({n_2} – {n_1})$
$\omega = 2\pi (1200 – 600)\frac{{rad}}{{min}} = \frac{{2\pi \times 600}}{{60}}\frac{{rad}}{s}$$ = 20\pi \frac{{rad}}{s}$
$\omega = 2\pi (1200 – 600)\frac{{rad}}{{min}} = \frac{{2\pi \times 600}}{{60}}\frac{{rad}}{s}$$ = 20\pi \frac{{rad}}{s}$
Standard 11
Physics
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