A fan is making 600 revolutions per minute. I | vedclass

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Question

(b) Increment in angular velocity $\omega = 2\pi ({n_2} - {n_1})$

$\omega = 2\pi (1200 - 600)\frac{{rad}}{{min}} = \frac{{2\pi 	imes 600}}{{60}}\f

Vedclass · Accepted Answer

$20\,\pi \,rad/\sec $

Vedclass · Answer

(b) Increment in angular velocity $\omega = 2\pi ({n_2} - {n_1})$

$\omega = 2\pi (1200 - 600)\frac{{rad}}{{min}} = \frac{{2\pi 	imes 600}}{{60}}\frac{{rad}}{s}$$ = 20\pi \frac{{rad}}{s}$

A fan is making $600$ revolutions per minute. If after some time it makes $1200 $ revolutions per minute, then increase in its angular velocity is

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