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3-2.Motion in Plane
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A stone ties to the end of a string $1\,m$ long is whirled in a horizontal circle with a constant speed. If the stone makes $22$ revolution in $44$ seconds, what is the magnitude and direction of acceleration of the stone
A$\frac{{{\pi ^2}}}{4}\;m{s^{ - 2}}$ and direction along the radius towards the centre
B${\pi ^2}\;m{s^{ - 2}}$ and direction along the radius away from the centre
C${\pi ^2}\;m{s^{ - 2}}$ and direction along the radius towards the centre
D${\pi ^2}\;m{s^{ - 2}}$ and direction along the tangent to the circle
(AIPMT-2005) (AIIMS-2014)
Solution
(c) $a = \frac{{{v^2}}}{r} = {\omega ^2}r$ $ = 4{\pi ^2}{n^2}r = 4{\pi ^2}{\left( {\frac{{22}}{{44}}} \right)^2} \times 1$ $ = {\pi ^2}\,m/{s^2}$
and its direction is always along the radius and towards the centre.
and its direction is always along the radius and towards the centre.
Standard 11
Physics
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