- Home
- Standard 11
- Physics
3-2.Motion in Plane
easy
A particle is revolving in a circular path of radius $25 \,m$ with constant angular speed $12 \,rev/min$. Then the angular acceleration of particle is .......... $rad / s ^2$
A$2 \pi^2$
B$4 \pi^2$
C$\pi^2$
D$0$
Solution
(d)
Angular acceleration is the rate of change of angular speed or angular velocity if $\vec{\omega}$ remains constant then
$\alpha=0$
Angular acceleration is the rate of change of angular speed or angular velocity if $\vec{\omega}$ remains constant then
$\alpha=0$
Standard 11
Physics
