Gujarati
14.Probability
medium

A five digit number is formed by writing the digits $1, 2, 3, 4, 5$ in a random order without repetitions. Then the probability that the number is divisible by $4$ is

A

$\frac{3}{5}$

B

$\frac{{18}}{5}$

C

$\frac{1}{5}$

D

$\frac{6}{5}$

Solution

(c) The number is divisible by $4$ if last two digits are $12, 24, 32$ and $52$. Remaining three places can be filled by $3!$ ways.
$\therefore $ Favouable cases = $3\,!\,\, \times \,\,4$
Required probability = $\frac{{3\,!\,\, \times 4}}{{5!}} = \frac{1}{5}$.

Standard 11
Mathematics

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