Gujarati
Hindi
6.System of Particles and Rotational Motion
easy

A flywheel of moment of inertia $0.32\ kg-m^2$ is rotated steadily at $120\,rad/\sec $ by a $50\,W$ electric motor. The kinetic energy of the flywheel is.......... $J$

A

$4608$

B

$1152$

C

 $2304$

D

$6912$

Solution

Kinetic energy ${K_R} = \frac{1}{2}I{\omega ^2}$

$ = \frac{1}{2}(0.32)\,{(120)^2}$

$= 2304\ J.$

Standard 11
Physics

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