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6.System of Particles and Rotational Motion
easy
A flywheel of moment of inertia $0.32\ kg-m^2$ is rotated steadily at $120\,rad/\sec $ by a $50\,W$ electric motor. The kinetic energy of the flywheel is.......... $J$
A
$4608$
B
$1152$
C
$2304$
D
$6912$
Solution
Kinetic energy ${K_R} = \frac{1}{2}I{\omega ^2}$
$ = \frac{1}{2}(0.32)\,{(120)^2}$
$= 2304\ J.$
Standard 11
Physics