A force of 50, dynes is acted on a body of mass 5 ,g which is at rest for an interval of 3 ,seconds

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4-1.Newton's Laws of Motion

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A force of $50\, dynes $ is acted on a body of mass $5 \,g$ which is at rest for an interval of $3 \,seconds$, then impulse is

A$0.15 \times {10^{ - 3}}\,Ns$

B$0.98 \times {10^{ - 3}}\,Ns$

C$1.5 \times {10^{ - 3}}\,Ns$

D$2.5 \times {10^{ - 3}}\,Ns$

Solution

(c)Impulse, $I = F \times \Delta t = 50 \times {10^{ – 5}} \times 3$=$1.5 \times {10^{ – 3}}\;N{\rm{ – }}s$

Standard 11

Physics

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