Gujarati
Hindi
4-1.Newton's Laws of Motion
normal

In the figure the tension in the diagonal string is $60\,N$.

Find the magnitude of the horizontal force $\overline{ F }_1$ and $\overline{ F }_2$ that must be applied to hold the system in the position shown.

A

$\frac{60}{\sqrt{2}}\,N$

B

$\frac{60}{\sqrt{3}}\,N$

C

$\frac{20}{\sqrt{2}}\,N$

D

$\frac{40}{\sqrt{2}}\,N$

Solution

$F_1=F_3=T \cos 45^{\circ}=60 \times \frac{1}{\sqrt{2}}=\frac{60}{\sqrt{2}}\,N$

$W=\frac{60}{\sqrt{2}}\,N$

Standard 11
Physics

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