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13.Oscillations
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A force of $20\,dyne$ applied to the end of spring increase its length of $1\, mm$, then force constant will be what ?
Option A
Option B
Option C
Option D
Solution
$k=\frac{\mathrm{F}}{\Delta l}=\frac{20}{0.1}=200 \mathrm{dyne} / \mathrm{cm} .$
Standard 11
Physics
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