A force-time graph for a linear motion is shown in figure where segments are circular. linear moment

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4-1.Newton's Laws of Motion

easy

A force-time graph for a linear motion is shown in figure where the segments are circular. The linear momentum gained between zero and $8$ second is

$ - 2\pi \,newton \times second$

$Zero\;newton \times second$

$ + 4\pi \,newton \times second$

$ - 6\pi \,newton \times second$

Solution

(b)As the area above the time axis is numerically equal to area below the time axis therefore net momentum gained by body will be zero because momentum is a vector quantity.

Standard 11

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medium

A force-time graph for a linear motion is shown in figure where the segments are circular. The linear momentum gained between zero and $8$ second is

Solution

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