A function $f(\theta )$ is defined as $f(\theta )\, = \,1\, - \theta + \frac{{{\theta ^2}}}{{2!}} - \frac{{{\theta ^3}}}{{3!}} + \frac{{{\theta ^4}}}{{4!}} + ...$ Why is it necessary for $f(\theta )$ to be a dimensionless quantity ?
A function $f(\theta )$ is defined as $f(\theta )\, = \,1\, - \theta + \frac{{{\theta ^2}}}{{2!}} - \frac{{{\theta ^3}}}{{3!}} + \frac{{{\theta ^4}}}{{4!}} + ...$ Why is it necessary for $f(\theta )$ to be a dimensionless quantity ?
Since, $f(\theta)$ is a sum of different power of $\theta$ and as $RHS$ is dimensionless, hence $LHS$ should also be dimensionless.
Similar Questions
If $C$ and $L$ denote capacitance and inductance respectively, then the dimensions of $LC$ are
If $C$ and $L$ denote capacitance and inductance respectively, then the dimensions of $LC$ are
The value of gravitational acceleration $C.G.S.$ system is $980 \;cm / sec$ ? .find the value of $g$ in $M.K.S$ system?
The value of gravitational acceleration $C.G.S.$ system is $980 \;cm / sec$ ? .find the value of $g$ in $M.K.S$ system?
The dimension of $\frac{\mathrm{B}^{2}}{2 \mu_{0}}$, where $\mathrm{B}$ is magnetic field and $\mu_{0}$ is the magnetic permeability of vacuum, is
The dimension of $\frac{\mathrm{B}^{2}}{2 \mu_{0}}$, where $\mathrm{B}$ is magnetic field and $\mu_{0}$ is the magnetic permeability of vacuum, is
- [JEE MAIN 2020]
If velocity $v$, acceleration $A$ and force $F$ are chosen as fundamental quantities, then the dimensional formula of angular momentum in terms of $v,\,A$ and $F$ would be
If velocity $v$, acceleration $A$ and force $F$ are chosen as fundamental quantities, then the dimensional formula of angular momentum in terms of $v,\,A$ and $F$ would be
The dimensions of $K$ in the equation $W = \frac{1}{2}\,\,K{x^2}$ is
The dimensions of $K$ in the equation $W = \frac{1}{2}\,\,K{x^2}$ is