1.Units, Dimensions and Measurement
easy

The dimensions of physical quantity $X$ in the equation Force $ = \frac{X}{{{\rm{Density}}}}$ is given by

A

${M^1}{L^4}{T^{ - 2}}$

B

${M^2}{L^{ - 2}}{T^{ - 1}}$

C

${M^2}{L^{ - 2}}{T^{ - 2}}$

D

${M^1}{L^{ - 2}}{T^{ - 1}}$

Solution

(c) $[X] = [F] × [\rho] $ $= [ML{T^{ – 2}}] \times \left[ {\frac{M}{{{L^3}}}} \right] $ $= [{M^2}{L^{ – 2}}{T^{ – 2}}]$

Standard 11
Physics

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