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1.Units, Dimensions and Measurement
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The Martians use force $(F)$, acceleration $(A)$ and time $(T)$ as their fundamental physical quantities. The dimensions of length on Martians system are
A
$F{T^2}$
B
${F^{ - 1}}{T^2}$
C
${F^{ - 1}}{A^2}{T^{ - 1}}$
D
$A{T^2}$
Solution
(d) Acceleration = $\frac{{{\rm{distan}}{\rm{ce}}}}{{{\rm{tim}}{{\rm{e}}^2}}}$ $⇒ A = L{T^{ – 2}} \Rightarrow L = A{T^2}$
Standard 11
Physics
Similar Questions
medium
medium
Match the following two coloumns
Column $-I$ | Column $-II$ |
$(A)$ Electrical resistance | $(p)$ $M{L^3}{T^{ – 3}}{A^{ – 2}}$ |
$(B)$ Electrical potential | $(q)$ $M{L^2}{T^{ – 3}}{A^{ – 2}}$ |
$(C)$ Specific resistance | $(r)$ $M{L^2}{T^{ – 3}}{A^{ – 1}}$ |
$(D)$ Specific conductance | $(s)$ None of these |
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