Gujarati
10-1.Thermometry, Thermal Expansion and Calorimetry
easy

If a cylinder of diameter $1.0\, cm$ at $30°C$ is to be solid into a hole of diameter $0.9997\, cm$ in a steel plate at the same temperature, then minimum required rise in the temperature of the plate is ........ $^oC$ (Coefficient of linear expansion of steel $ = 12 \times {10^{ - 6}}°C^{-1}$)

A

$25$

B

$35$

C

$45$

D

$55$

Solution

(a) $\alpha = \frac{{\Delta L}}{{{L_0}\Delta \theta }} = \frac{{(1 – 0.9997)}}{{0.9997 \times 12 \times {{10}^{ – 6}}}} = 25°C$

Standard 11
Physics

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