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11.Thermodynamics
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A gas for which $\gamma = 1.5$ is suddenly compressed to $\frac{1}{4}$ th of the initial volume. Then the ratio of the final to the initial pressure is
A
$1:16$
B
$1:8$
C
$1:4$
D
$8:1$
Solution
(d) ${P_1}V_1^\gamma = {P_2}V_2^\gamma $==> $\frac{{{P_2}}}{{{P_1}}} = {\left[ {\frac{{{V_1}}}{{{V_2}}}} \right]^\gamma } = {\left[ {\frac{4}{1}} \right]^{3/2}} = \frac{8}{1}$
Standard 11
Physics
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