Gujarati
11.Thermodynamics
easy

A gas for which $\gamma = 1.5$ is suddenly compressed to $\frac{1}{4}$ th of the initial volume. Then the ratio of the final to the initial pressure is

A

$1:16$

B

$1:8$

C

$1:4$

D

$8:1$

Solution

(d) ${P_1}V_1^\gamma = {P_2}V_2^\gamma $==> $\frac{{{P_2}}}{{{P_1}}} = {\left[ {\frac{{{V_1}}}{{{V_2}}}} \right]^\gamma } = {\left[ {\frac{4}{1}} \right]^{3/2}} = \frac{8}{1}$

Standard 11
Physics

Similar Questions

Start a Free Trial Now

Confusing about what to choose? Our team will schedule a demo shortly.