Gujarati
Hindi
1. Electric Charges and Fields
normal

A given charge situated at a distance $r$ from an electric dipole on it axis experiences a force $F$. If the distance of the charge from the dipole is doubled, the force acting on the charge will be

A

$4F$

B

$F/2$

C

$F/4$

D

$F/8$

Solution

Force exerted by an electric dipole on a charge is inversely proportional to the cube of distance of the charge from the centre of the dipole.

$\mathrm{F} \propto \frac{1}{\mathrm{r}^{3}}$

$\therefore \quad \frac{\mathrm{F}}{\mathrm{F}^{\prime}}=\left(\frac{\mathrm{r}^{\prime}}{\mathrm{r}}\right)=\left(\frac{2}{1}\right)^{3}$ or $\quad \mathrm{F}^{\prime}=\frac{\mathrm{F}}{8}.$

Standard 12
Physics

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