A graph between square of velocity of a particle and distance s moved by particle is shown in figure

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2.Motion in Straight Line

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A graph between the square of the velocity of a particle and the distance $s$ moved by the particle is shown in the figure. The acceleration of the particle is $...........m/s^2$

A

$-8$

B

$-25$

C

$-16$

D

$-4$

Solution

(d)

$v^2=u^2+2 a s, \text { slope }=2 a=-\frac{16}{2}=-8\,m / s ^2$

or

$a=-4\,m / s ^2$

Standard 11

Physics

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