A grinding wheel attained a velocity of 20,ra | vedclass

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Question

$\omega_{i}=0$

$\omega_{\mathrm{f}}=20$

$f=5$

$	heta=?$

$	heta=\left(\frac{\omega_{i}+\omega_{f}}{2}ight) 	imes t=50$

Number of re

Vedclass · Accepted Answer

$\frac {25}{\pi }$ revolution

Vedclass · Answer

$\omega_{i}=0$

$\omega_{\mathrm{f}}=20$

$f=5$

$	heta=?$

$	heta=\left(\frac{\omega_{i}+\omega_{f}}{2}ight) 	imes t=50$

Number of revolution $=\frac{	heta}{2 \pi}=\frac{25}{\pi}$

A grinding wheel attained a velocity of $20\,rad/sec$ in $5\,sec$ starting from rest. Find the number of revolution made by the wheel

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