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4-1.Newton's Laws of Motion
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A jet of liquid of cross-sectional area $'a'$ strikes a wall making angle $\theta $ with wall. The water strikes with the wall with velocity $v$ and rebounds elastically. If density of liquid be $\rho $, the normal force on the wall is
A$2a{v^2}\rho \,\sin \,\theta $
B$2a{v^2}\rho \,\cos \,\theta $
C$2av\rho \,\sin \,\theta $
D$2av\rho \,\cos \,\theta $
Solution
Normal force = change in normal component of momentum per
$sec = \frac{2mv\,sin\,\theta }{t} = 2[av\rho ]v\,sin\,\theta = 2av^2 \rho \,sin\,\theta $
$sec = \frac{2mv\,sin\,\theta }{t} = 2[av\rho ]v\,sin\,\theta = 2av^2 \rho \,sin\,\theta $
Standard 11
Physics
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