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6.Permutation and Combination
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A lady gives a dinner party for six guests. The number of ways in which they may be selected from among ten friends, if two of the friends will not attend the party together is
A
$112$
B
$140$
C
$164$
D
None of these
Solution
(b) Either $6$ selected out of $8$ or one from $2$ and $5$ from $8$ $ = {\,^8}{C_6}\, + {\,^2}{C_1}\, + {\,^8}{C_5}\, = \,140$.
Standard 11
Mathematics
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