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Question

Let conductivity of steel ${K_{steel}{ = }}k\,then$

From question

Conductivity of copper ${K_{copper}} = 9k$

${	heta _{copper}} =

Vedclass · Accepted Answer

$90$

Vedclass · Answer

Let conductivity of steel ${K_{steel}{ = }}k\,then$

From question

Conductivity of copper ${K_{copper}} = 9k$

${	heta _{copper}} = {100^ \circ }C$

${	heta _{steel}} = {0^ \circ }C$

${l_{steel}} = {l_{copper}} = \frac{L}{2}$

From formula temperature of junction;

$	heta  = \frac{{{K_{copper}}{	heta _{copper}}{l_{steel}} + {k_{steel}}{	heta _{steel}}{l_{copper}}}}{{{K_{copper}}{l_{steel}} + {K_{steel}}{l_{copper}}}}$

$ = \frac{{9k 	imes 100 	imes \frac{L}{2} + k 	imes 0 	imes \frac{L}{2}}}{{9k 	imes \frac{L}{2} + k 	imes \frac{L}{2}}}$

$ = \frac{{\frac{{900}}{2}}}{{\frac{{10kL}}{2}}} = {90^ \circ }C$

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